Biology 50, Second Midterm Exam
Prof. J. Dangl
Tuesday, Oct. 13, Coker 201
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PLEDGE: I neither gave nor received help on this exam. SIGNED:
Please read ALL questions CAREFULLY before starting. Answer in as short a manner as possible--writing down a lot of words won’t
necessarily help. Note that a Genetic Code table is
provided on the last page.
1. (6 pts.) In a cross between Hfr ala+ str-s x F- ala- Str-r, what medium should the mating pairs be plated to select for
Ala+ Str-r recombinants? Which are the selected and counterselected markers? Which strain is a prototrophic for alanine production
and which is
auxotrophic?
2. (8 pts.) A lambda phage mutant was discovered lacking a functional integrase gene. Could this mutant still function as
a specialized transducing phage? Would it still infect E. coli? Explain.
3. (10 pts.) Consider the following Hfr x F- cross:
Hfr genotype: a+ b+
c+ str-s
F- genotype: a-
b- c- str-r
where the order of transfer is: a 9
minutes
b 11 minutes
c 30 minutes
Recombinants are selected by palting on a medium that lacks particular nutrients (a, b, c) and contains Streptomycin. Which of
the following are TRUE and which are FALSE:
a) a+ str-r colonies are
approx. equal to b+ str-r colonies
b) a+ str-r colonies > c+
str-r colonies
c) b+ str-r colonies < c+
str-r colonies
d) Among the total colonies
selected for b+ str-r , the a+ b+ str-r are approx. equal to those
selected for
a- b+ str-r.
e) Among the total colonies
selected for a+ c+ str-r, the a+ b+ c+ str-r < a+ b- c+ str-r.
4. (5pts.) In a mating of Hfr pro+ tpr+ ala+ tet-s x F- pro- trp- ala- gly+ tet-r, cells are interrupted after several minutes
and PLATED ON MEDIA CONTAINING THE AMINO ACIDS SHOWN BELOW. Based on the number of colonies, what is the
order of gene transfer? What is the counterselectable marker?
proline +
alanine 290 colonies
tryptophan +
proline 120 colonies
tryptophan +
alanine 45 colonies
5. (10pts.) For the aspects of transcription and translation listed below, write “E” if the statement applies to Eukaryotes
ONLY “P” if the statement applies to Prokaryotes ONLY and “BOTH” if it applies to both Prokaryotes and Eukaryotes and
“NEITHER” if the statement is false.
a) Translation begins at an AUG
codon.
b) mRNA molecules are usually
the products of splicing of a longer primary transcript.
c) The mRNA has a 5’ capped
nucleotide.
d) One polycistronic mRNA can
encode many different proteins.
e) Translation requires
ribosomes.
f) After transcription, a run of
“A” ribonucleotides is added to the mRNA.
g) RNA polymerase recognizes
promoter elements in the DNA to begin transcripton.
h) Transcription and translation
are coupled.
i) Charged tRNA molecules are
used to add amino acids to growing polypeptides.
j) Uncharged tRNAs released from
the ribosome are degraded.
6. (6pts.) If the DNA molecule below
is transcribed left to right,
5'-TCGACTTGCAGGACCCTGCGGTAC-3'
3'-AGCTGAACGTCCTGGGACGCCATG-5'
then what is:
a) the mRNA
sequence?
b) the amino acid
sequence?
c) What would be the
effect of a C-->A mutation at position #9 in the DNA sequence?
7. (2pts.) What structural interaction of charged tRNA and mRNA molecules determines whether tRNA will stay bound to the
ribosome “A site” long
enough for a peptide bond to be formed?
8. (8pts.) In studies on a hypothetical protein, you identify the mutants below which have no activity. What is the mutation(s)
responsible for each amino acid sequence? Show the DNA sequence of each.
Wild type protein Thr Val
Tyr Glu Asn
His Ser Lys
Wild type DNA ACC GTC TAC GGA AAC CAC AGC AAA
Mutant #1 Thr Val
ACC GTC
Mutant #2 Thr Val Ser Glu Thr Thr
Ala
ACC GTC
Mutant #3 Thr Val Tyr Ala Asn His Ser Lys
ACC
GTC TAC G
Mutant #4 Thr Gly Leu Arg
Asp His Ser Lys
ACC
G
9. (4 pts.) When Crick and Brenner performed the experiments which led to the conclusion that the Genetic Code is a
non-overlapping triplet code, they started their analyses with a mutation caused by Proflavin. What is the key phenotypic feature of
this mutation, and what conclusion drawn from
this feature, were critical to the success of their experiments?
10. (4pts.) Why is attenuation not used as a regulatory mechanism
in Eukaryotes?
11. (10pts.) For the following genotypes and conditions (+ or - lactose), predict with a checkmark in the correct column,
whether functional enzyme
(b-galactosidase) or no enzyme is
made:
Genotype Lactose? Functional No
enzyme?
enzyme?
I+ O+ Z+ -
I+ OC
Z+ +
I- O+ Z+ -
I- O+ Z-
+
I- O+
Z+ / F’I+ -
I+ OC
Z+ / F’O+ -
I+ O+
Z- / F’I+ O+ Z+
+
I- O+ Z- / F’ I+ O+ Z+ -
IS
O+ Z- / F’ OC
Z+ -
I+ OC
Z+ / F’ O+ Z+ +
12. (12pts.) The tryptophan (trp)
operon is controlled at various levels.
a)
When free tryptophan levels are high in a bacterium, how is transcription of
the trp operon regulated?
b)
When free tryptophan is low, but charged tRNA-trp is still present, how is
transcription regulated?
c)
Diagram the situation reflected in part (b).
d)
Diagram the situation when charged tRNA-trp levels are very low, or absent.
e)
What is the end outcome of the situation you drew in (D)?
f) A mutant which is constitutive for production of Trp operon mRNA maps to the attenuator region, the region which normally
encodes the short leader peptide.
What is the probable nature of this mutation?
13. (9pts.) When glucose is present in an E. coli cell, is the concentration of free cAMP high or low? Can a mutant with either
an inactive adenyl cyclase gene or an inactive CRP gene synthesize B-galactosidase? Does the binding of cAMP-CRP to DNA effect
the binding of Repressor?
14. (6pts.) Genes A and B map very close to each other. In a deletion mutation, both A and B enzyme activity are missing and
neither A nor B protein are made. Instead, a novel protein is made in which the 30 amino acids at the amino terminus derive from
B and the 30 amino acids of A at the carboxyl terminus derive from A.
a) What respect to the 5’ to 3’
orientation of the coding strand of DNA, what is the gene order of A and B?
b) What inference can be made
regarding the number of bases deleted in this mutant?